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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: dianzhang on April 20, 2012, 10:23:16 am

Title: Diff Clac
Post by: dianzhang on April 20, 2012, 10:23:16 am

let f:(-pi/4 , pi/4) -> R , F(x) = tan(2x). A tangent to the graph of y=F(x) where x=a makes and angle of 70" with the positive direction of the x-axis. Find the possible values of a.

I started off by sketching the graph of y=tan(2x) realized there should be two possible answers within the domain of (-pi/4 , pi/4). but i dont know how do i continue on from there?
could anyone help? :)



mod edit: removed random poll and included it in the post

Title: Re: Diff Clac
Post by: Hutchoo on April 20, 2012, 07:51:26 pm

I did this question yesterday:

Quote from: TrueTears on April 19, 2012, 08:16:09 pm

Which question do you need answered?


As for the other question - tan(70*180/pi) is the gradient of the tangent.

now diff f(x), then find the x values for when the derivative of f(x) is equal to tan(70*180/pi) subject to the restriction of the domain. In other words, solve f'(x) = tan(70*180/pi)

Title: Re: Diff Clac
Post by: dianzhang on April 25, 2012, 11:44:56 am

did you find out how to do it?