ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: Yendall on July 24, 2012, 07:06:56 pm
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t_(n+2)= t_(n+1)+ t_n where t_(1 )=a,t_2=7 and t_5=27
The value of a is?
Just in regards to this equation, can I use this to solve:
d= (t_b- t_a)/(b-a)
d= (27-7)/(5-2)
d= 20/3=6.66667
7-6.66667=0.33,rounds to, a=0
This doesn’t seem right, and I’m not sure what the actual answer is, but is this method feasible?
[EDIT]
nevermind, i realised how stupid I sounded.