ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: vcestudent94 on November 07, 2012, 09:25:27 pm

Title: help
Post by: vcestudent94 on November 07, 2012, 09:25:27 pm: How do you convert: sqrt(sqrt(3)+2)/2 to--> (sqrt(6)+sqrt(2))/4
I hope thats clear
Title: Re: help
Post by: BubbleWrapMan on November 07, 2012, 09:45:41 pm: $\frac{\sqrt{\sqrt{3}+2}}{2}=\frac{2\sqrt{\sqrt{3}+2}}{4}=\frac{\sqrt{4(\sqrt{3}+2)}}{4}=\frac{\sqrt{4\sqrt{3}+8}}{4}=\frac{\sqrt{6+4\sqrt{3}+2}}{4}=\frac{\sqrt{(\sqrt{6})^{2}+2\cdot\sqrt{2}\cdot\sqrt{2}\cdot\sqrt{3}+(\sqrt{2})^{2}}}{4}=\frac{\sqrt{(\sqrt{6})^{2}+2\cdot\sqrt{6}\cdot\sqrt{2}+(\sqrt{2})^{2}}}{4}=\frac{\sqrt{(\sqrt{6}+\sqrt{2})^{2}}}{4}=\frac{\sqrt{6}+\sqrt{2}}{4}$

But needless to say you wouldn't have to do that in tech-free
Title: Re: help
Post by: HighLatency on November 07, 2012, 09:53:56 pm: Convert sqrt(3)+2 into polar form
Sqrt the polar form using the theorem thingo
Convert the polar form back into Cartesian
Put into original and bam, answer
Title: Re: help
Post by: BubbleWrapMan on November 07, 2012, 10:03:22 pm: Wait, what's the polar form of that
Title: Re: help
Post by: HighLatency on November 07, 2012, 11:55:01 pm: Quote from: ClimbTooHigh on November 07, 2012, 10:03:22 pm
Wait, what's the polar form of that
O crap...
Yeah that doesn't work xD
Title: Re: help
Post by: Biceps on November 08, 2012, 09:06:52 am: LOL i was waiting for that :PP