ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: j23 on January 22, 2013, 10:08:04 pm
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i'm having some trouble on spec essentials book chapter 1A Toolbox exercise 1E.
Does anyone have a cheat sheet or the formula to how to find a specific term number or the values within a sequence? Or even the sum of an infinite sequence? (Im using the CAS new black calc). Thanks !!
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I feel your pain! I have the same CAS (TI -Nspire CX CAS) and when I tried to solve using the CAS nothing happened!I did for like an hour before I just gave up!
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Are S&S even part of Specialist Mathematics? I don't remember learning about them.
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Are S&S even part of Specialist Mathematics? I don't remember learning about them.
yea they included it this year, unfortunately :(
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You guys look at sequences and series now? Awesome!
What is the actual question?
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the study design hasn't changed since 2006 and sequences and series isn't in the maths quest book, so it's not going to be on the exams, right?
sequences and series is from GMA, and i think chapter 1 of the essentials book is GMA revision
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Yeah its just in the toolbox. Not sure if it will be in the final exam.
And theres no specific question, i'm just stuck on the whole chapter. Heres an example though!
"A difference equation has rule y(n+1)=2y(n)+6, y(1)=5. Find y(2) and y(3). Use a graphics calculator to find y(10)"
*Note the brackets aren't actually brackets, there the little numbers under the letter! :P
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Ok so basically you have a sequence
, where
with initial condition
.
The first part is easy:


I have never used a CAS calculator, but this problem can be very easily be done in MATLAB, Mathematica, WolframAlpha?, ... My result is that
= 5626.
My code is:
y[1] = 5;
y[n_] := 2*y[n-1] + 6;
This link may be helpful.
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Thanks so much QuantumJG. I've finished all the questions now except one that says
"The fibonacci sequence is given by the difference equation t(n+2)=t(n+1)+t(n) where t1=t2=1. Find the first ten terms of the fibonacci sequence.
And so i type in y[n_] := y[n-1]+y[n-2)
y[1]=1
however whenever i type in my calculator dies and i've done it 5 times! am i typing in something wrong?
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Thanks so much QuantumJG. I've finished all the questions now except one that says
"The fibonacci sequence is given by the difference equation t(n+2)=t(n+1)+t(n) where t1=t2=1. Find the first ten terms of the fibonacci sequence.
And so i type in y[n_] := y[n-1]+y[n-2)
y[1]=1
however whenever i type in my calculator dies and i've done it 5 times! am i typing in something wrong?
Ok, the first part is correct, but you need to include the next condition. So what you need to type is:
y[n_] := y[n-1] + y[n-2]
y[1] = 1
y[2] = 1
The reason why it crashed is because if you tried to find y[3], your calculator would say y[3] = y[2] + y[1], but you didn't define y[2].
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Series and sequences yay :) :) :) is it the one in further maths or the one that you use epsilon for addition and pi for multiplication?