ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: saba.ay on February 09, 2013, 08:48:56 am
-
Please help with the question below. I'm completely lost as to how to do it. :/
-
You can make a right angled triangle at the edge of the top disk. That will leave x^2+30^2 = 32^2, and you can solve for x. The radius of the base is hence 20+x, and then you need to double that to find the diameter.
-
You can make a right angled triangle at the edge of the top disk. That will leave x^2+30^2 = 32^2, and you can solve for x. The radius of the base is hence 20+x, and then you need to double that to find the diameter.
Sorry, why is the radius 20+x and not 10+x , which is them doubled to get a diameter of 20+ 2x?
-
wouldnt the diametre of the base be 20 + 2root(62)
-
Sorry, why is the radius 20+x and not 10+x , which is them doubled to get a diameter of 20+ 2x?
You are correct; pretty sure appianway just made a typo/had a brain fade :P
-
Yup whoops typo ^^ Completely right!