Post by: 9_7 on May 18, 2013, 01:13:14 pm
y-2=loge(5x-2) with the domain (2/5, 6]
I drew it but apparently its incorrect?? :/
Post by: Zealous on May 18, 2013, 03:53:53 pm
You can always sketch the graph on your CAS with a restricted domain in order to see if your graph matches up with the question.
By the way, did they give you a restriction on the domain or did you restrict it yourself?
Post by: 9_7 on May 18, 2013, 05:01:36 pm
Hi, what do you mean you drew it but "apparently" its incorrect?
You can always sketch the graph on your CAS with a restricted domain in order to see if your graph matches up with the question.
By the way, did they give you a restriction on the domain or did you restrict it yourself?
They gave me the restriction. My teacher said the answer started at the point when y is 1 or something, I'm really confused
Post by: Scooby on May 18, 2013, 08:12:02 pm
Hey guys, can someone guide me through this question??
y-2=loge(5x-2) with the domain (2/5, 6]
I drew it but apparently its incorrect?? :/
Rearrange to make y the subject
There's a vertical asymptote where
Let
Therefore there is a vertical asymptote where
You can essentially ignore the vertical translation in determining the shape of the graph (but not the axes intercepts)
To find the y-value of the endpoint, sub
Therefore the endpoint is at
You can find the x-intercept but solving
Hope that helped! :)