ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Physics => Topic started by: andysalter on September 09, 2013, 10:20:53 pm
-
In a game of snooker a player hit's a 0.2 kg ball with the cue, exerting a force of 40N on the ball for 12 milliseconds.
a) What impulse is exerted on the ball?
I = f x t = 40 (in newtons) x 0.12 (in seconds) = 4.8 Ns the answer says 0.48 Ns, what did I do wrong?
b) What is the change in momentum of the ball?
Newton's 1st law? Final momentum = initial momentum
therefore momentum = 4.8 kg ms-1 answer says 0.48 kg ms-1
c) With what velocity will the ball leave the cue?
I = m x V => V = I / m = 4.8 / 0.2 = 24 ms-1 answer says 2.4 ms-1
all the answers are the same as mine just divided by 10... where did I need to do that?
-
12 ms = 0.012 s
That's all.
-
hahahaha I feel stupid now, thanks ;D
-
Time conversions - notorious for tripping Physics students over