ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: Chazef on November 05, 2013, 09:19:40 pm
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okay so just before I go to bed I want to know whether I've done this question right :)
A binomial distribution of the random variable X, with six independent trials, is such that Pr ( X = 3) = Pr ( X = 4). If p is the probability of a success on any trial, find the value of p.
I got p=0,1,4/7 but I'm not sure if 0 or 1 are permissible, could anybody clear this up (hopefully 4/7 is actually a correct solution too)
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I got 4/7, too. I feel like we can't dismiss 0 or 1, because unless there's something in the question that you haven't told me, they're also right.