ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Physics => Topic started by: methodsboy on August 24, 2009, 02:17:54 pm
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hey
i have never seen a graph like this and im not sure how to do question 248 (highlighted):
[IMG]http://img196.imageshack.us/img196/8186/questioncvx.jpg[/img]
It's from a VCAA exam, so i trust that the Vs isn't a typo and that it's meant to be Vs not Ek. Could someone please give some guideance as to how to approach a graph such as this. Thanks :)
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its just the y intercept, 2eV or 2 * 1.6 * 10^(-19) J
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its just the y intercept, 2eV or 2 * 1.6 * 10^(-19) J
But should the y-intercept be labelled as Ek not Vs?
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its just the y intercept, 2eV or 2 * 1.6 * 10^(-19) J
But should the y-intercept be labelled as Ek not Vs?
doesn't matter which one, you can just convert it
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its just the y intercept, 2eV or 2 * 1.6 * 10^(-19) J
But should the y-intercept be labelled as Ek not Vs?
doesn't matter which one, you can just convert it
okay thanks :)