Post by: almostdonewithschooling on January 13, 2018, 10:37:17 pm
Just wondering,
Is this right?
Aluminium metal reacts with aqueous copper (II) nitrate
Would be:
Al(s) + Cu(NO3)2(aq) ---> Al(NO3)2 + Cu(s) when you balance it?
Thankss
Post by: Yertle the Turtle on January 13, 2018, 11:22:26 pm
Hey guys,Aluminum makes a 3+ ion, so it will be Al(NO3)3 instead. Therefore the balancing will be different:
Just wondering,
Is this right?
Aluminium metal reacts with aqueous copper (II) nitrate
Would be:
Al(s) + Cu(NO3)2(aq) ---> Al(NO3)2 + Cu(s) when you balance it?
Thankss
2Al(s) + 3Cu(No3)2(aq) → 2Al(No3)3(aq) + 3Cu(s)
Post by: almostdonewithschooling on January 13, 2018, 11:54:42 pm
Doesn't make sense because the Ba is a metal and SO is a non-metal. (S) is meant to be metal and metallic right?
(http://uploads.tapatalk-cdn.com/20180113/23b1b1f1c604003083d5cdc771c2d353.jpg)
Post by: Lear on January 14, 2018, 12:04:25 am
Post by: Yertle the Turtle on January 14, 2018, 12:14:32 am
Haha oopsy. Could you also tell me why the right side state is in (s) and (aq)?Don't think of it as the (S) being by itself, think of it as being a sulfate ion, and therefore when it is part of an ionic compound with a metal it can be solid or aqueous, and here is where you use your solubility laws to find out if it is soluble or insoluble. Just a side point, this formula is incorrect, as it hasn't been balanced. I don't know if that occurs later in the video or not, but just remember this anyway. Always balance :P
Doesn't make sense because the Ba is a metal and SO is a non-metal. (S) is meant to be metal and metallic right?
(http://uploads.tapatalk-cdn.com/20180113/23b1b1f1c604003083d5cdc771c2d353.jpg)