ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: chuckjefster90 on October 08, 2009, 06:29:21 pm
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How do u find relevant intervals and solve abs(x^2-4)-5 alebraically?
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|x^2-4|=5
x^2-4=5 and x^2-4=-5
x^2-9 and x^2+1=0
x= +-3
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THNX
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|x^2-4|=5
x^2-4=5 and x^2-4=-5
x^2-9 and x^2+1=0
x= +-3
But also be careful to remember the domain for each hybrid function :P
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^ he didn't do it like that. A very good and quick way, no need to worry about domain, that would be a round about way.
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^ he didn't do it like that. A very good and quick way, no need to worry about domain, that would be a round about way.
I know but didn't OP said "find relevant intervals"
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oh yeah lol i just focused on the reply and it looked like he was solving