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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: kj2001 on April 03, 2018, 11:02:12 am

Title: Help with Circular Functions transformation question
Post by: kj2001 on April 03, 2018, 11:02:12 am
Hi
Can anyone help with this question
State a sequence of two  transformations that takes the graph f to the new graph h.

f:[0,4] --- R  f(x) = 6 sin (nx/2)   to h:[-3,1]---R, h(x) = 6 cos (nx/2)    That n should read as a pi sign.

I have tried reflecting in each axis, and translated 3 and 4 units to the left but can't get it to fit neatly into the (-3,1) domain.

Thanx KJ
Title: Re: Help with Circular Functions transformation question
Post by: VanillaRice on April 03, 2018, 11:51:53 am
Hi there,

I'm not sure what you mean by "translated 3 and 4 units to the left", but try:

- Reflection in the y-axis
- Translation of 1 unit to the right (in the positive x-direction)

Using the symmetry properties of sin and cos, you should be able to get to the final domain and answer.

Hope this helps :)
Title: Re: Help with Circular Functions transformation question
Post by: MAGGOT on April 03, 2018, 03:31:22 pm
Similar to what Vanilla was thinking.
→ Graph the 2 functions and apply the symmetry properties of sin and cos