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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: mandy on October 13, 2009, 06:18:09 pm

Title: Displacement and Velocity
Post by: mandy on October 13, 2009, 06:18:09 pm: The position of a body between the times t=0 and t=10 is given by the equation x = t²-6t+5, where t is the time in seconds and x is the position in metres.
a. Sketch the position-time graph for 0<t<10.
Done
b. Calculate the average velocity between 2s and 4s.
0m/s
c. Calculate the average velocity between 1s and 5s.
0m/s
d. Calculate the average speed between 2s and 4s.
I tried finding the turning pt. of the graph and using that to find the distance travelled, but that was wrong.
How do I do this question?
Title: Re: Displacement and Velocity
Post by: arthurk on October 13, 2009, 06:56:52 pm: The answers are in ur bio exams
if u get what im saying
Title: Re: Displacement and Velocity
Post by: TrueTears on October 13, 2009, 07:01:26 pm: Avg speed is defined as $\frac{\mbox{total distance traveled}}{\Delta t}}$
Title: Re: Displacement and Velocity
Post by: mandy on October 13, 2009, 08:14:45 pm: Okay, so here was my way of doing this..
I tried to find the turning point of x=t²-6t+5, and I got the turning point of (3,-4).
I then added this to the distance of 5. ---> 5+4+4=13
Then, I divided the 13 by 2, which is the change in time, i hope.
I got an answer of 6.5m/s, while the correct answer is meant to be 1m/s :S
Help please ?
Title: Re: Displacement and Velocity
Post by: mandy on October 13, 2009, 08:29:46 pm: Okay, thank you, I got it :)