ATAR Notes: Forum
HSC Stuff => HSC Science Stuff => HSC Subjects + Help => HSC Chemistry => Topic started by: melonsinwater on October 07, 2018, 07:23:26 pm
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http://puu.sh/BH2an/d6838c82eb.png
https://puu.sh/BH28Q/c9193f0207.png
How do you find the answer to these questions? (q19 and 20)
Please answer in detail. Thank you.
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http://puu.sh/BH2an/d6838c82eb.png
https://puu.sh/BH28Q/c9193f0207.png
How do you find the answer to these questions? (q19 or 20)
Please answer in detail. Thank you.
Hi, so these are my solutions to these questions:
Q19
=\frac{0.13}{278.1}=4.67\times10^{-4}molL^{-1}\\n(Pb^{2+})=4.67\times10^{-4}molL^{-1}\\c(Pb6{2+}=\frac{4.67\times10^{-4}}{0.05}=9.3\times10^{-3}molL^{-1}\, \therefore C)
Q20
\times25}\\=4.38Jper116.2gheptan-1-ol\\\frac{44.38}{116.2}=0.38kg\, \therefore D)