ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: thisongaintgottaname on October 27, 2009, 01:56:11 pm
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heyy!
i have a question here,
A particle moves in a straight line with acceleration of a=x+6 at time t. Given that x=1,v=7, the velocity of the particle is?
is it 土(x+6) or is it just -(x+6) ?
thank you very much!
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 = x + 6 )

Sub in x = 1, v = 7





 )
lol sorry for all that working, I just read your question properly (so drained straight after exam right now :P)
but when x = 1, v = 7
Hence take positive as if you took negative then v = -7
so yeah
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woo long working! thank you NE2000!!xD
this is a MAV 2004 exam question. i doubted the accuracy of the answer as it states the answer be 土(x+6). i am sure the solution is wrong now.
thanks again!! :D
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heyy!
i have a question here,
A particle moves in a straight line with acceleration of a=x+6 at time t. Given that x=1,v=7, the velocity of the particle is?
is it 土(x+6) or is it just -(x+6) ?
thank you very much!
the first time I read your question... the answer of 7 came to head immediately, but then after reading the question again, I realised it was asking for the velocity function in terms of t. haha. lol :D
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^^ lol. Normally it should say the velocity at time 't'. I wonder whether you'd get a mark for saying 7... (wouldn't bet on it)