ATAR Notes: Forum
HSC Stuff => HSC Science Stuff => HSC Subjects + Help => HSC Physics => Topic started by: Jefferson on October 03, 2019, 07:21:02 pm
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Does anyone know how to solve?
The source answer is A, people debating over B (because half a revolution produces 12V, then another half produced 12V to make 24V).
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I might be wrong here, but doesn't it produce 12V per one whole rotation?
Here is my reasoning:
emf = -N(d(Φ)/dt)
= (-200(0.05 x 0.162)) / (1/46.8 )
= -11.98V
= (approx) 12V
And since I used 1/46.8 it should be one rotation produces 12V (because it takes 1/46.8s for it to spin one rotation)
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I might be wrong here, but doesn't it produce 12V per one whole rotation?
Here is my reasoning:
emf = -N(d(Φ)/dt)
= (-200(0.05 x 0.162)) / (1/46.8 )
= -11.98V
= (approx) 12V
And since I used 1/46.8 it should be one rotation produces 12V (because it takes 1/46.8s for it to spin one rotation)
Sure, but the change in flux for half a rotation is
0.05 * 0.16^2. This is because it goes from 0 degrees to 180 degrees.
So for a full rotation, it should be 2 * 0.05 * 0.16^2
That's where the 24 is coming from.