Post by: Studyinghard on November 24, 2009, 06:19:50 pm
(IO3)- to I-
reduction half equation. How do i do this.
thanks
Post by: Edmund on November 24, 2009, 06:33:07 pm
Add three
Now add
And finally add 6 electrons to the left side to balance the charge
Post by: Studyinghard on November 24, 2009, 07:48:16 pm
2KNO3 (s) ----> 2KNO2(s) + O2 (g)
1.01g of potassium nitrate was decomposed.
calculate amount of mol of Oxygen produced.
answer says 0.02. wtf?
Post by: Edmund on November 24, 2009, 08:15:12 pm
Looking at mol ratio, there will be 0.5 x 0.00999 = 0.004995 mol of O2
Now looking at KNO2, there will be 0.00999 mol of
But how many O2? According to equation, there's two NO2. Therefore the total number of O2 is 2, so number of moles is 2 x 0.00999 = 0.01988 mol
Adding all up, 0.004995 + 0.01988 = 0.02
Post by: Studyinghard on November 24, 2009, 08:16:59 pm
First you find the moles of potassium nitrate which is 0.00999 mol
Looking at mol ratio, there will be 0.5 x 0.00999 = 0.004995 mol of O2
Now looking at KNO2, there will be 0.00999 mol of(1:1 ratio)
But how many Oxygen? According to equation, there's two
Adding all up, 0.004995+0.01988 = 0.02
:S why would you times it by 2. shouldnt u halve it? cuz the mole of oxygen is 1.
Post by: Edmund on November 24, 2009, 08:21:38 pm
Quote
Now looking at KNO2, there will be 0.00999 mol of (1:1 ratio)
But how many Oxygen? According to equation, there's two . Therefore the total number of O2 is 2, so number of moles is 2 x 0.00999 = 0.01988 mol
This is for the oxygen in the KNO2 molecule. In the equation, it shows 2KNO2, which means two sets of O2, so we times the moles by 2.
I think the question is asking for the total amount of oxygen produced which includes the one in KNO2?
(Sorry latex doesnt seem to be working)
Post by: Studyinghard on November 24, 2009, 08:38:52 pm
QuoteNow looking at KNO2, there will be 0.00999 mol of (1:1 ratio)
But how many Oxygen? According to equation, there's two . Therefore the total number of O2 is 2, so number of moles is 2 x 0.00999 = 0.01988 mol
This is for the oxygen in the KNO2 molecule. In the equation, it shows 2KNO2, which means two sets of O2, so we times the moles by 2.
I think the question is asking for the total amount of oxygen produced which includes the one in KNO2?
(Sorry latex doesnt seem to be working)
oh so im confusing myself with the oxygen gas produced and they are asking for the oxygen solid produced?
Post by: Edmund on November 24, 2009, 09:02:03 pm
I think so, I can't get 0.02 if it's just the gas....QuoteNow looking at KNO2, there will be 0.00999 mol of (1:1 ratio)
But how many Oxygen? According to equation, there's two . Therefore the total number of O2 is 2, so number of moles is 2 x 0.00999 = 0.01988 mol
This is for the oxygen in the KNO2 molecule. In the equation, it shows 2KNO2, which means two sets of O2, so we times the moles by 2.
I think the question is asking for the total amount of oxygen produced which includes the one in KNO2?
(Sorry latex doesnt seem to be working)
oh so im confusing myself with the oxygen gas produced and they are asking for the oxygen solid produced?