ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: shokstar on February 07, 2010, 10:11:50 pm
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What volume of 0.100 M sulfuric acid would be required to neutralise a solution containing 0.500g of sodium hydroxide and 0.800g of potassium hydroxide?
Im very confused. Thanks
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Maybe i shouldve searched first the forum first.
Please delete
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1) find the n(OH-)
0.5/m(NaOH) + 0.8/m(KOH) = n(OH-)
neutralisation is where n(H+) = (OH-) therefore it is the same. n(H2SO4) = 2 x n(H+)
2) n(H2SO4) = 2xn(OH-)
3) volume required is 10 x n(H2SO4) because it is a 0.1 molar solution.
sorry, no calc...