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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: vidang on April 19, 2010, 08:08:04 pm

Title: Commeting on slope
Post by: vidang on April 19, 2010, 08:08:04 pm
i'm not quiet sure how to comment on slope

for example:

Gold Medals = -2.50 + 1.31 x Olympiad

how would comment if the intercept is negative or you just ignore it?
Title: Re: Commeting on slope
Post by: naved_s9994 on April 19, 2010, 08:13:46 pm
Its in the textbook Im preety sure...
I know its in the essential book, for sure atleast.

Dont have book on me though so I dont remember exact wordings..
But Its something similar to like "On average, for each rise in Olympiads, there is 1.33 (something - sorry dont remember at all) rise in gold medals, or something across those lines.
Title: Re: Commeting on slope
Post by: stonecold on April 19, 2010, 08:36:19 pm
you would probably have to include what happens initially to get full marks, so:

initially the number of gold medals is (x intercept), and increases by an average of 1.33 per olympiad.

actually a better answer would be:
up until the (x-intercept) olympiad, the number of gold medals is zero, after which the number of  gold medal increases by 1.33 per olympiad on average.
Title: Re: Commeting on slope
Post by: vidang on April 19, 2010, 09:02:41 pm
x intercept?
Title: Re: Commeting on slope
Post by: stonecold on April 19, 2010, 09:11:02 pm
draw the graph in your calc and you'll see what i'm talking about...
Title: Re: Commeting on slope
Post by: Blakhitman on May 02, 2010, 06:23:10 pm
Would it be something like, up until the 2nd olympiad (x-int), the gold medals received equal to 0, after which the number of  gold medal increases by 1.33 per olympiad on average.

haha finish off my sac tomorrow, and got a negative y-int for House prices against average earnings.
Title: Re: Commeting on slope
Post by: Visionz on May 02, 2010, 06:51:31 pm
The gold medal tally increases by 1.31 each Olympiad.