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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: mojomojo on May 23, 2010, 04:47:22 pm

Title: Simple boxplot question
Post by: mojomojo on May 23, 2010, 04:47:22 pm

In Checkpoint 2010, there's a question regarding to boxplot - A1 Core question 23 .

"The number of customers who spent more than 90 seconds moving along this aisle is closest to"
a) 7 b) 20 c) 26 d) 75 e) 79

Basically, the boxplot shows that there're 79 customers, upper whisker starts from 90 along with 7 outliers in the end.
So what i did was (79 - 7) x 0.25 + 7 = 25
But the answer shows that it's 79 x 0.25 = 19.75 = B

HMMM i thought the body and whiskers of the box does not include outliers?

Title: Re: Simple boxplot question
Post by: akira88 on May 23, 2010, 10:23:30 pm

Have a look at the assessment report, this question was from the 2008 Exam 1 :)
http://www.vcaa.vic.edu.au/vcaa/vce/studies/mathematics/further/assessreports/2008/further_maths1_assessrep_08.pdf
There is an explanation there, hope it helps.