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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: samiira on June 18, 2010, 12:53:50 am

Title: One more question.. :(
Post by: samiira on June 18, 2010, 12:53:50 am: The path of a locus is given by 4x^2 + 3y^2 =12

Q1. Find Area of locus?
Q2. What is the transformation steps from x^2 + y^2 =12
Title: Re: One more question.. :(
Post by: Mao on June 18, 2010, 01:48:21 am: $A = \pi a b$ , where a and b are the 'radius' lengths of the major and minor axis
Title: Re: One more question.. :(
Post by: /0 on June 18, 2010, 01:19:53 pm: You can try direct integration of $y = \pm \sqrt{\frac{12-4x^2}{3}}$