ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: kenhung123 on August 22, 2010, 11:50:10 am
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Is this reaction exo or endo?
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As far as i know, this reaction is a simple dilution and no energy is produced or absorbed. And i can't find an enthalpy value for it anywhere, so it's neither exo nor endo
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Yea but SO3+H2O=H2SO4 is also dilution and is exo though
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its exothermic.
Its not a dilution.
SO3 + H2O = H2SO4 releases too much energy thus the sulfuric acid forms into a mist which is too hard to collect therefore we split this equation in to 2 and effectively you split the energy released. Lets call energy released here amount "C"
So we put it into two equations the first being
SO3 + H2SO4= H2S2O7 ENERGY IS RELEASED but less than "C" so lets call it "A"
Then
H2S2O7 + H2O = 2H2SO4 energy again is released but ALSO less than "C" so no mist of h2so4 is formed Call energy released "B"
A + B must = C. but by splitting up the equation you allow less heat generated in such short amount of time.
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Wow that was very intelligent of you to figure that out. Thanks.
Is the chamber which H2S2O7+H2O not called the diluter?
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dilution tower?? the oleum is simply hydrated to produce sulfuric acid, dont know where u got dilution tower from :/
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Ok thanks
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Yeah it is called the diluter.