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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: wildareal on October 16, 2010, 02:36:24 pm

Title: Polar Coordinates Question
Post by: wildareal on October 16, 2010, 02:36:24 pm

The polar equation of the circle with centre [3,TT/2] and radius 3? Thanks. The answer is r=6sin(theta). How do you get to it?
Thanks.

Title: Re: Polar Coordinates Question
Post by: wildareal on October 16, 2010, 03:45:02 pm

Do you go from:

x^2+(y-3)^2=9 and then sub in rcos(theta) and rsin(theta) ?

Title: Re: Polar Coordinates Question
Post by: TrueTears on October 16, 2010, 03:53:46 pm

yeah let x = rcos(theta) and y be the other one