ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: matt123 on October 22, 2010, 06:40:26 pm
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hey guys
i spotted a few mistakes
id appreciate it if someone double checked these for me.
multiple choice 16 is C .. they said B
the first equilibrium question .. thy say the units are M^3 . but its M^2
also Q5B ... part ii...
they said that N(e) = n(mol fe3+) .. but .. it should be
n(mol fe3+) = 1/3(n(e)).
make sense?
can someone please double check the last one.
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post question?
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post question?
Its in like 5 diff parts .. hard to put up all the info
hold on .. ill try
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yeah sounds right, pretty stupid on the solutions behalf (assuming these are correct)
on that note, does anyone have a soft copy of the solutions? thanks in adv.
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oops, for 5bii they are right;
Fe3+ + e -> Fe2+
1 to 1 ratio between Fe3+ and e
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Heres the solutions Jason
And for question 2 - its actually M3 because you cant have concentrations of solids (no M) it's just counted as 1
I thought I had tsfx beat too until my teacher explained it ;P
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Heres the solutions Jason
And for question 2 - its actually M3 because you cant have concentrations of solids (no M) it's just counted as 1
I thought I had tsfx beat too until my teacher explained it ;P
True.
but if its just counted as 1.
then the ratio is
1 : 3.
.. hence there is 2 mol MORE on the right side
and so it should be M2
im confused?
unless ur saying .. because its a solid . its counted as 0.
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Well for the concentration fraction to be defined, it technically can't be zero. And you can't have a concentration of a solid so we just assign it a quantity of 1 (not 1M). [i.e The ratio is M3:1]
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Well for the concentration fraction to be defined, it technically can't be zero. And you can't have a concentration of a solid so we just assign it a quantity of 1 (not 1M). [i.e The ratio is M3:1]
Ohh kk
sounds good
cheers