ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE General & Further Mathematics => Topic started by: xD_aQt on October 30, 2010, 03:34:24 pm

Title: feasible region
Post by: xD_aQt on October 30, 2010, 03:34:24 pm

how does it actually work :o
like how would you decide which region to shade
whether its the top or bottom half  :-\
any help would be appreciated

Title: Re: feasible region
Post by: Hutchoo on October 30, 2010, 03:43:54 pm

Maybe this will help :S?

Title: Re: feasible region
Post by: jasoN- on October 30, 2010, 03:47:39 pm

Well firstly, you'd need to draw in the missing inequality (y=x/3)
given y>x/3, it must be above this line (and including)
given y<x/2, it must be below this line (and including)
given y<24-x, it must be below this line (and including)
must be above lines x>0 and y>0 (and including)

If you're still not convinced about your answer, sub in a 'test' point that is 'obviously' inside the region
Try (10,4) in each inequality, it will satisfy all inequalities

Title: Re: feasible region
Post by: xD_aQt on October 30, 2010, 04:53:18 pm

so if the test point is inside the region, then its part of the feasible region right?

Title: Re: feasible region
Post by: jasoN- on October 30, 2010, 04:55:57 pm

yes (this is just a method to test if you were indeed right, it's not working out or anything)

Title: Re: feasible region
Post by: xD_aQt on October 30, 2010, 04:58:38 pm

okay :)