ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: lisafaustina on October 31, 2010, 11:37:02 am
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Ok so when u have somethig like
Sketch {z: Arg(z) < -pi/4 } how do you sketch this in the complex plane? I dunno which area to shade in..
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The angle from (0,0) is lower than -pi/4.
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Could someone please roughly sketch this graph?
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Shade all of quadrant 3 and the half of quad 4 that's UNDER the *ray*. Have the *ray* dotted.. I think that's right. Correct me if wrong anyone..
Lol soz kept referring to the ray as arc**
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Don't forget to open circle the origin and dotted lines!
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Negative Re(z) axis should also be dotted.. and yes, open circle on origin
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1 thing i feel weird about, is when they give u an axis and ask u to sketch like Arg(z)=-pi/4, how are we supposed to dot the -ve x axis so that its clear-.-
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Lol it's hard to draw a frickin dotted line OVER their lines :( usually i use a red pen to do it but scared i can't rub it out if it turns out to be incorrect
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agreed. I always get scared I'm doing it wrong.. Thanks for this question though, coz I remembered I need to revise region shading in complex plane....
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Thanks. What if it's like {z: Arg(z) < or = -pi/4}
and what if it's {z: Arg(z) > -pi/4}
when do you have an open circle on origin and when do you have a closed circle?
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{z: Arg(z) < or = -pi/4} is dotted -ve Re(z) axis and full line at -pi/4
{z: Arg(z) > -pi/4} is dotted line at pi/4 and full line at -ve Re(z) axis as -pi<Arg(z)< and = pi
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Rays always have open circle on their starting point. If it's Arg(z), (0,0) has open circle. If it's Arg(z-(1+3i), (1,3) has an open circle. Arg(z) < or = to -pi/4 means make the ray solid, not dotted, but KEEP negative Re(z) axis dotted. EDIT: Also keep same shading as Arg(z) < -pi/4..
Arg(z) > -pi/4 means dotted ray and shade quad 1 2 and the half of 4 that's above the ray, NO quad 4. Also dot the neg Re(z) axis.
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Rays always have open circle on their starting point. If it's Arg(z), (0,0) has open circle. If it's Arg(z-(1+3i), (1,3) has an open circle. Arg(z) < or = to -pi/4 means make the ray solid, not dotted, but KEEP negative Re(z) axis dotted. EDIT: Also keep same shading as Arg(z) < -pi/4..
Arg(z) > -pi/4 means dotted ray and shade quad 1 2 and the half of 4 that's above the ray, NO quad 4. Also dot the neg Re(z) axis.
Arg(z) > something , doesn't that mean -ve x axis is solid, since -pi < Arg(z) </= pi.
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Rays always have open circle on their starting point. If it's Arg(z), (0,0) has open circle. If it's Arg(z-(1+3i), (1,3) has an open circle. Arg(z) < or = to -pi/4 means make the ray solid, not dotted, but KEEP negative Re(z) axis dotted. EDIT: Also keep same shading as Arg(z) < -pi/4..
Arg(z) > -pi/4 means dotted ray and shade quad 1 2 and the half of 4 that's above the ray, NO quad 4. Also dot the neg Re(z) axis.
Arg(z) > something , doesn't that mean -ve x axis is solid, since -pi (greater) Arg(z) (greater of equal to) pi.
Good point. You're probs right... Neg Re(z) axis being dotted should only happen on instances such as Arg(z) > pi/4. Good pick up. Sorry about confusion :S
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OKEY so for further clarification, Arg(z) > and = or > angle means DOT -ve Re(z). Arg(z)< or = or < angle means -ve Re(z) should be included...
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OKEY so for further clarification, Arg(z) > and = or > angle means DOT -ve Re(z). Arg(z)< or = or < angle means -ve Re(z) should be included...
Thats upside down. What 99.95 4 sure posted is right Arg> include -ve Re(z), Arg < exclude. Thats it for x-axis.
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But doesn't Arg(z) have a range of -pi < angle < or = pi ?? In saying that, wouldn't that mean that if Arg(z) > angle it will INCLUDE the negative Re(z) axis because it reads it as +pi ? and if so, wouldn't Arg(z) < / = angle mean that -pi ( -ve Re(z) ) is not included thus dotted because of the range?
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what i meant by -pi < Arg(z) </= pi is that for all values of Arg(z) must lie between -pi(excluded) to pi (included)
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Good, yes, sounds right (Y)
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ok is this correct?
i just did this on paint
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if that is including pi, then yes
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yeah the -ve x-axis should be solid.
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aw what i thought -ve x-axis was always dotted :SSS
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IF the angle's positive, -ve x-axis is solid, if the angle is -ve, the -ve x-axis is dotted.
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not true; eg
 \geq -\frac{\pi}{3})
What you're trying to say is if
or
then -ve x-axis is solid (ie. pi)
Likewise if
or
then -ve x-axis is dotted
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I'm never gonna get explaining it right, am I? :/ Oh well...
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Whats the difference in the diagrams of Arg(z)>=-3pie/4 and z:-3pie/4<=Arg(z)<=0 ???
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Arg(z)>=-3pie/4 covers 1st 2nd and 4th quad fully. -ve x-axis is solid, ray is solid and half of 3rd quad that's under the ray is covered.
z:-3pie/4<=Arg(z)<=0 covers only half of third quad that's under the ray, and all of quad 4. +ve x-axis is included..
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ahhhhh i see cheers mate.