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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: sajib_mostofa on November 03, 2010, 09:33:51 pm

Title: Wrong answer?
Post by: sajib_mostofa on November 03, 2010, 09:33:51 pm
I just did the 2010 NEAP exam 1 and for Q3c, the graph has a closed circle at (2,2) according to the solutions. But shouldnt it be at (2,4)?
Title: Re: Wrong answer?
Post by: Elnino_Gerrard on November 03, 2010, 09:37:21 pm
I dont  even    get how they got the rule? :(

how do u know u have to take the negative root of (x-2)2
Title: Re: Wrong answer?
Post by: Linkage1992 on November 03, 2010, 09:39:44 pm
The equation of the graph will simply be y = x. The point (2,4) doesn't lie on this line.
You have to sub in the value for which the domain of f(x) ends, and this is at x = 2, so you get the endpoint as (2,2)
Title: Re: Wrong answer?
Post by: sajib_mostofa on November 03, 2010, 09:42:59 pm
@Elnino_gerrard, The domain of the origin is from , which becomes the range of the inverse. Hence you take the negative square root.
Title: Re: Wrong answer?
Post by: sajib_mostofa on November 03, 2010, 09:44:42 pm
The equation of the graph will simply be y = x. The point (2,4) doesn't lie on this line.
You have to sub in the value for which the domain of f(x) ends, and this is at x = 2, so you get the endpoint as (2,2)
How do you know that (2,4) doesn't lie on the line?
Title: Re: Wrong answer?
Post by: Linkage1992 on November 03, 2010, 09:45:12 pm
I dont  even    get how they got the rule? :(

how do u know u have to take the negative root of (x-2)2

The domain of the graph is (-infinity, 2) as you found from the previous question. This means the range of the inverse function will have to be (-infinity, 2). Thus, you have to choose the option which gives this range, and so you take the negative root, as the other option doesn't give you the required range.
Title: Re: Wrong answer?
Post by: Linkage1992 on November 03, 2010, 09:47:15 pm
The equation of the graph will simply be y = x. The point (2,4) doesn't lie on this line.
You have to sub in the value for which the domain of f(x) ends, and this is at x = 2, so you get the endpoint as (2,2)
How do you know that (2,4) doesn't lie on the line?

The equation is y = x.  4 does not equal 2 and so that point cannot lie on the line.
Title: Re: Wrong answer?
Post by: Elnino_Gerrard on November 03, 2010, 09:54:09 pm
I dont  even    get how they got the rule? :(

how do u know u have to take the negative root of (x-2)2

The domain of the graph is (-infinity, 2) as you found from the previous question. This means the range of the inverse function will have to be (-infinity, 2). Thus, you have to choose the option which gives this range, and so you take the negative root, as the other option doesn't give you the required range.
Isnt it just like f(g(x))
How do we know that its the domain of the inside function that becomes the domain of the the whole function? :|:(
Im so lost
Title: Re: Wrong answer?
Post by: Elnino_Gerrard on November 03, 2010, 09:54:46 pm
I mean we aint finding an inverse here so how does the whole domain range swapping thing come into play?
Title: Re: Wrong answer?
Post by: Souljette_93 on November 03, 2010, 09:57:09 pm
I dont  even    get how they got the rule? :(

how do u know u have to take the negative root of (x-2)2

The domain of the graph is (-infinity, 2) as you found from the previous question. This means the range of the inverse function will have to be (-infinity, 2). Thus, you have to choose the option which gives this range, and so you take the negative root, as the other option doesn't give you the required range.
Isnt it just like f(g(x))
How do we know that its the domain of the inside function that becomes the domain of the the whole function? :|:(
Im so lost


that's the rule.