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VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Physics => Topic started by: cameron_15 on November 06, 2010, 05:30:29 pm

Title: Accelerating electrons... Old study design?
Post by: cameron_15 on November 06, 2010, 05:30:29 pm
Hey guys, I'm doing the older VCAA stuff and there are questions about accelerating electrons through potential differences. I have one formula on my cheat sheet which allows me to solve these, however I was not taught this in class.

Is it something I should know?

if yes, what are any relevant formulas I might like to have?

thanks guys.
Title: Re: Accelerating electrons... Old study design?
Post by: schnappy on November 06, 2010, 05:40:30 pm
I was taught this. It's important to experiments, but light&matter doesn't really have a prac component to it so I'd be very surprised to see it on the exam.
Title: Re: Accelerating electrons... Old study design?
Post by: cameron_15 on November 06, 2010, 05:45:45 pm
I was taught this. It's important to experiments, but light&matter doesn't really have a prac component to it so I'd be very surprised to see it on the exam.

damn smart kids in year 11 that know more than me! :)

Just kidding, The formula I have on my cheat sheet (I stole most of it off one from here) is

Volts=h^2 / (2mq(lamda)^2)

Is there anything else I should know? I use this to find wavelength then do equations from their.
Title: Re: Accelerating electrons... Old study design?
Post by: Galvanic Cell on November 07, 2010, 07:22:15 pm
Im pretty sure its just part of the synchorotron now..
Title: Re: Accelerating electrons... Old study design?
Post by: Chavi on November 07, 2010, 07:29:43 pm
I was taught this. It's important to experiments, but light&matter doesn't really have a prac component to it so I'd be very surprised to see it on the exam.
I've come across this in '10 third party exams. There is a strong chance it will be on the exam.

Just remember that Ek=eV and then simply rearrange to find the desired unknown (Ek = hc/lamda or Ek=hf)