ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: madoscar65 on December 14, 2010, 05:50:56 pm

Title: Inverse circular function question!!
Post by: madoscar65 on December 14, 2010, 05:50:56 pm

Hi guys,
I've been trying to find the domain and range of this equation of y=arccos(x^2). I've got the domain to be [-1,1], but I got the range to be [0,pi] but the answer says [0,pi/2]. Please help and please show me how you did it.

Thanks

Title: Re: Inverse circular function question!!
Post by: brightsky on December 14, 2010, 06:00:53 pm

y = arccos(x^2) --> cos(y) = x^2

0 =< cos(y) =< 1 in this case so 0 =< y =< pi/2