ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: Ematuro on February 26, 2011, 09:46:19 am
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A manganese ore was analysed by titration with a freshly prepared acidified iron(II) sulfate solution.
The manganese was first oxidised to permanganate ion (MnO4−). The permanganate obtained from a 0.269 g sample of ore required a titre of 22.41 mL of 0.500 M FeSO4 solution to reach the endpoint.
How would you go about writing an equation for this?
I began with Mn --> MnO4-
But the answer does it the other way round. I dont get why? I mean in the equation it says permanganate obtained FROM a 0.269g sample of ore. So how come in the solutions they put it the other way round? Or did I misinterpret something?
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Well the Mn --> MnO4 is the first part of the solution.
The second part is where } + Fe^{2+}_{(aq)} + 8H^{+}_{(aq)} \xrightarrow ~Mn^{2+}_{(aq)} +4H_{2}O + 5Fe^{3+}_{(aq)})
The permanganate reacts with Iron to change colour and form the Manganese ions.
P.S OMG I just learnt how to write equations in forum!
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But the answer does it the other way round. I dont get why? I mean in the equation it says permanganate obtained FROM a 0.269g sample of ore. So how come in the solutions they put it the other way round? Or did I misinterpret something?
You didn't misinterpret. But the titration actually occurs with the permanagate. Think of obtaining permanganate from the ore as a process BEFORE the titration is conducted.
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OH! I get it now thanks! I guess I didn't fully read the question properly after all
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This sounds a lot like the steel wool prac...