ATAR Notes: Forum
VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: DNAngel on March 14, 2011, 11:11:16 am
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This is a question from the Heinemann Chemistry 2 textbook, and it goes like this:
When 0.100g of white phosphorus is burned in oxygen, 0.228g of an oxide of phosphorus is produced. The molar mass of the oxide is 284 gmol^-1.
a) Determine the empirical formula of the phosphorus oxide
b) Determine the molecular formula of the phosphorus oxide
Yeah, so my main trouble is writing out the equation and solving for the unknown mole ratios of the phosphorus oxide.
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first we set the equation out this way:
Px + KO2 --> PxOk2
Now we started off with 0.1g of phosphorus, and 0.228g of product was producted. That means that the unaccounted 0.128g must be the collective mass of the oxygen. therefore the ratio is:
0.100:0.128
then using the standard empirical formula methods divide by the respective molecular mass so P =30.97 and O2 =32 (or 16 if you choose to ignore the "2" in the equation)
and you get 0.003228:0.004 or 0.008
divide by the smallest
1:1.24 (or 2.5) multiple the ratios till you get a whole number ratio in this case it is 4 (or 2)
4:5 (or 2:5)
so sub the values back into the questions
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Thank you very much. It was a very helpful explanation and I managed to get the correct answer too ;D