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VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Physics => Topic started by: Lols123 on June 06, 2011, 07:08:03 pm

Title: Quick Elec Question
Post by: Lols123 on June 06, 2011, 07:08:03 pm: How come the points calculated from the gain (i.e. VOut in Vin x Gain)
Dont match up with the initial graph of Vout vs VIn graphed?

Edit: Answers attached as well.
Title: Re: Quick Elec Question
Post by: Vincezor on June 06, 2011, 10:03:23 pm: Quote from: Lols123 on June 06, 2011, 07:08:03 pm
How come the points calculated from the gain (i.e. VOut in Vin x Gain)
Dont match up with the initial graph of Vout vs VIn graphed?

Edit: Answers attached as well.

Arghh Insight 2009? Answer is most definitely wrong. I'm pretty sure a few people have posted this question, I'll try to find the thread but I'll tell you now, the answer is incorrect as that would only be correct if the amplifier's linear region extended much further left and right of the graph. If I remember correctly, the output signal was largely clipped as well.
Title: Re: Quick Elec Question
Post by: Lols123 on June 06, 2011, 10:15:45 pm: yeah lol, looked really weird haha
thanks for that confirmation :P

also not sure on this one :S
would you be able to explain it to me D:
Title: Re: Quick Elec Question
Post by: FromBaghdadWithLove on June 06, 2011, 10:20:28 pm: the probe is the vout and the v out is 9v..? something like that i think lol

after that do u have any clue how to do this
Title: Re: Quick Elec Question
Post by: Vincezor on June 06, 2011, 10:39:34 pm: Isn't this the answer (see attached) This is because when the input voltage is +-100mV, the output voltage does not show any clipping. Hence, it is still operating in the linear region?
Title: Re: Quick Elec Question
Post by: FromBaghdadWithLove on June 06, 2011, 10:45:15 pm: i dont have the answers but i think thats correct, since i thought thats the answer b4, thanks :)