ATAR Notes: Forum

VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: onlyfknhuman on November 06, 2008, 10:25:11 pm

Title: some Log laws clarifaction
Post by: onlyfknhuman on November 06, 2008, 10:25:11 pm: $3^x = e^loge(3)(x) = e^loge(3^x)$ are these corrrect.

I dont know how to put e^loge[3] etc on latex can anyone tell me as well.
Title: Re: some Log laws clarifaction
Post by: Mao on November 06, 2008, 10:27:23 pm: Code: [Select]
3^{x}=e^{\log_e (3) x} = e^{\log_e (3^{x})}
and yes, they are correct.
Title: Re: some Log laws clarifaction
Post by: onlyfknhuman on November 06, 2008, 10:29:05 pm: awesome, Mao.
Title: Re: some Log laws clarifaction
Post by: rowshan on November 06, 2008, 10:30:10 pm: $3^{x}=e^{\log_e (3) x} = e^{\log_e (3^{x})}$