ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: onlyfknhuman on November 07, 2008, 08:17:15 am
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Area = 1
and its continuous right?
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yep
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In methods, do we have to prove:
 \ge 0, x \epsilon R)

And continuous?
Or just the area? Quite tedious to prove the other two at times <_<
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It does not have to be continuous
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how come?
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Yeh I was thinking about that after...doesn't need to be continuous does it? Theres plenty of distributions which just cut off. But they have to at least be defined over R yes? (i.e. no 'gaps' in the domain. Everything must be assigned a value, even if it means y=0)
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It does not have to be continuous
I can kind of see your point... however, it has to have a definite area bound by two ends though.
for example, you cannot define a continuous random probability function for
(unless, of course, k is infinitesimal.... but lets not go into that)
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ah fudge i see.
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It does not have to be continuous
I can kind of see your point... however, it has to have a definite area bound by two ends though.
PDFs must have definite end points. yo.
for example, you cannot define a continuous random probability function for
(unless, of course, k is infinitesimal.... but lets not go into that)