ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: Roflmao on November 07, 2008, 08:07:58 pm
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Find the number below 50, a multiple of 4 the sum of its didgits is 5
a 2 - digit number a multiple of 7 the product of it's digits is 16
a square number below 50, the sum of its digits is 9
I was hoping someone can explain these to me
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This is all i got to.
We have a two-digit number, the sum of its digits is 5.
There are only five such numbers: .\begin{Bmatrix}14 \\ 23 \\ 32 \\ 41 \\ 50 \end{Bmatrix}
Only one is a multiple of 4: .32
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Reason why i didnt bother with maths in my younger days...
Sounds like a maths tongue twister.
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Dare someone to use calculus (somehow) to solve this. GOGOGOGO
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1. 32
2. 28
3. 36
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nice
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1. 32
2. 28
3. 36
As for how to solve it, just guess. Trust me, it's MUCH faster than using algebra to solve them. I generally started with the second clue and worked out all the possible combinations, and checked them against the second clue.
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oh whoops i thought it said sum of the digits is 16
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Lol mao u are god of the maths
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LOL LEGEND :D
BOOM
i'm saving that lol