ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Specialist Mathematics => Topic started by: /0 on December 07, 2008, 07:43:19 pm
-
P, Q and R are points with position vectors
,
, and
(cbf with tildes) respectively relative to an origin O where
and
are non-zero, non-parallel vectors. Given that S is the point on OP produced such that
and
, evaluate k and m.
Does this seem like a flawed question to you? I drew the vectors on a graph and it seems R, Q, and S are not collinear.
Thanks
-
)
\vec{a} - (k+4)\vec{b})

Since 
\vec{a} - (k+4)\vec{b} = 2m\vec{a} - 3m\vec{b})
and
are non-zero, non-parallel vectors, which implies they are linearly independent.
(This must be true, for otherwise,
has a solution for
and
, which would imply
. This means that the two vectors are parallel, so by contradiction, they cannot be linearly dependent)
Since
and
are linearly independent, equating coefficients yields:
(1): 
(2): 
Solving them:
-
thanks coblin! (2) is meant to be
but yeah now I understand the method
-
thanks coblin! (2) is meant to be
but yeah now I understand the method
Ah, always messing up one step. :) Fixed
-
COLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLINNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN
-
what is up mate
-
just the ceiling
-
The sky.
-
sick kentz