ATAR Notes: Forum

VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Chemistry => Topic started by: dekoyl on December 25, 2008, 01:15:57 am

Title: Simple concentration question
Post by: dekoyl on December 25, 2008, 01:15:57 am: For a 0.20M solution of potassium sulfate, calculate the amount, in mol, of:
a) Potassium ions, $K^{+}$

The answer does this as first step:
a) n(K2SO4) = C × V = 0.20 × 0.250 = 0.050 mol

I think M was mol/L but why is V 250mL in this case?

Thanks.
Title: Re: Simple concentration question
Post by: vce08 on December 25, 2008, 01:17:33 am: i think you forgot to tell us some info
Title: Re: Simple concentration question
Post by: shinny on December 25, 2008, 01:18:13 am: Someone else already asked this somewhere. Long story cut short; the question is screwed up.
Title: Re: Simple concentration question
Post by: hard on December 25, 2008, 01:18:33 am: Quote from: dekoyl on December 25, 2008, 01:15:57 am
For a 0.20M solution of potassium sulfate, calculate the amount, in mol, of:
a) Potassium ions, $K^{+}$

The answer does this as first step:
a) n(K2SO4) = C × V = 0.20 × 0.250 = 0.050 mol

I think M was mol/L but why is V 250mL in this case?

Thanks.
that's weird, you must've not read the question properly i mean the volume cannot be just made up.
ehhh i'm still revising a bit of unit 1/2 chemistry. FUCK MID YEAR IS SO CLOSE!
Title: Re: Simple concentration question
Post by: dekoyl on December 25, 2008, 01:20:07 am: Quote from: hard on December 25, 2008, 01:18:33 am
FUCK MID YEAR IS SO CLOSE!
Oh shut up, mate. I hate hearing stuff like that :P Please don't get me nervous

Quote from: shinny on December 25, 2008, 01:18:13 am
Someone else already asked this somewhere. Long story cut short; the question is screwed up.
Ah thanks shinny =O
Title: Re: Simple concentration question
Post by: AQ on December 30, 2008, 08:58:59 pm: Quote from: hard on December 25, 2008, 01:18:33 am
Quote from: dekoyl on December 25, 2008, 01:15:57 am
For a 0.20M solution of potassium sulfate, calculate the amount, in mol, of:
a) Potassium ions, $K^{+}$

The answer does this as first step:
a) n(K2SO4) = C × V = 0.20 × 0.250 = 0.050 mol

I think M was mol/L but why is V 250mL in this case?

Thanks.
that's weird, you must've not read the question properly i mean the volume cannot be just made up.
ehhh i'm still revising a bit of unit 1/2 chemistry. FUCK MID YEAR IS SO CLOSE!

mid year is close?
Lol, i totally forgot about it.
Title: Re: Simple concentration question
Post by: khalil on December 30, 2008, 09:20:56 pm: Quote from: AQ on December 30, 2008, 08:58:59 pm
Quote from: hard on December 25, 2008, 01:18:33 am
Quote from: dekoyl on December 25, 2008, 01:15:57 am
For a 0.20M solution of potassium sulfate, calculate the amount, in mol, of:
a) Potassium ions, $K^{+}$

The answer does this as first step:
a) n(K2SO4) = C × V = 0.20 × 0.250 = 0.050 mol

I think M was mol/L but why is V 250mL in this case?

Thanks.
that's weird, you must've not read the question properly i mean the volume cannot be just made up.
ehhh i'm still revising a bit of unit 1/2 chemistry. FUCK MID YEAR IS SO CLOSE!

mid year is close?
Lol, i totally forgot about it.
Midyear will be a breeze. Its the end of year exams that are critical!