Uni Stuff > Mathematics

Dekoyl's Questions

(1/12) > >>

dekoyl:
Accidentally deleted post

enwiabe:
Row-echelon form means leading ones only, an upper triangle matrix.


So they want, (forgive the lack of latex)

[1  a  b |  c]
[0  1  d |  e]
[0  0  1 |  f]

meaning you have

z = f
y + dz = e
x + ay + bz = c

where a, b, c, d, e, and f are all arbitrary constants in the real set.

Back substitution then means subbing z = f into y + dz = e to obtain y = e - df

and then subbing in z = f and y = e - df into x + ay + bz = c to obtain x = c - bf - ae + adf

enwiabe:
P.S. Linear Algebra is finicky as hell, be very careful what you're multiplying/dividing/adding/subtracting in your row operations. One mistake and it will all go horrrrribly wrong. Check, double check, triple check.

squance:

--- Quote from: enwiabe on February 06, 2009, 10:46:05 pm ---P.S. Linear Algebra is finicky as hell, be very careful what you're multiplying/dividing/adding/subtracting in your row operations. One mistake and it will all go horrrrribly wrong. Check, double check, triple check.

--- End quote ---

Im currently doing Linear Algebra as a summer subject and yeah...be very careful with your row operations.
Also remember to use correct notation.

dekoyl:
Thanks enwiabe and squance. I think I've got it =D

Navigation

[0] Message Index

[#] Next page