Author Topic: Satellites (Read 1001 times) Tweet Share

TonyHem · « **on:** February 27, 2009, 08:25:36 pm »

The space shuttle is launched into orbit from a point A on the equator as shown. The shuttle then enters a stable circular orbit of radius Ro at point B. The radius of the Earth is 6.4 x 10^6 m. The ratio of the gravitational field strength at A to that at B is equal to 1.2. Calculate the distance Ro.

There's a diagram - can't really get it up but its page 98 in the Heinemann physics 12 book if anyone has it.

Mao · « **Reply #1 on:** February 27, 2009, 09:14:36 pm »

strength at A: $g_A=\frac{GM}{(6.4E6)^2}=1.2g_B$

strength at B: $g_B=\frac{GM}{R^2}$

hence, $\frac{GM}{(6.4E6)^2}=1.2\times \frac{GM}{R^2}$

$\implies R^2 = 1.2\times (6.4E6)^2$

$\implies R=7.0\times 10^6\; m$

TonyHem · « **Reply #2 on:** February 27, 2009, 10:36:49 pm »

k thanks get it now

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Author Topic: Satellites (Read 1001 times) Tweet Share

TonyHem

Satellites

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