Acid - Base Question.

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SDPHD

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Acid - Base Question.

« on: August 16, 2011, 06:01:22 pm »

0

I'm wondering how to do this question.

The answer seems pretty straight forward, but I don't know how or why you do what you're meant to do.

Any help is much appreciated, thanks.

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Vincezor

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Re: Acid - Base Question.

« Reply #1 on: August 16, 2011, 06:53:52 pm »

+2

As it is a neutral solution, $[D^+] = [OD^-]$

$K_d= 1.82*10^{-16} = (D+)^2$

$[D^+]=\sqrt{1.82*10^{-16}}=1.35*10^{-8}M$

=B?

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BoredSatan

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Re: Acid - Base Question.

« Reply #2 on: August 16, 2011, 08:15:56 pm »

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Looks correct Vincezor

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SDPHD

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Re: Acid - Base Question.

« Reply #3 on: August 16, 2011, 08:49:16 pm »

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Quote from: Vincezor on August 16, 2011, 06:53:52 pm

As it is a neutral solution, $[D^+] = [OD^-]$

$K_d= 1.82*10^{-16} = (D+)^2$

$[D^+]=\sqrt{1.82*10^{-16}}=1.35*10^{-8}M$

=B?

Makes sense now, thanks.

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BSc. UoM. SMD.

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