Help...!

[jane1234]

Okay we have a spesh SAC atm and I'm on the last question but it's not working...

Basically you have to find two equations:

N = 500e^(0.1-0.001*P)*t

and

P = 1/50*(2499(e^N*T/100) +1)

And then substitute in various values for t (eg t=2, t=3 etc) and then solve the equations simultaneously to get N and P.

The question, however, is asking me what will happen to N and P as t increases (if they will/will not end up reaching 0). Only problem is, my calculator wont solve past t=9.45 so I have no idea if N and P will eventually equal 0 or another value. I don't really know how to approach this any other way... why won't the calculator solve? Is it because I only have the old version (the 2009 one)

[xZero]

im assuming that you found a relationship between N and P, just sub that into one of the equation and it should tell you what happen to P and N.

[jane1234]

im assuming that you found a relationship between N and P, just sub that into one of the equation and it should tell you what happen to P and N.

Yeah did that, didn't work but it's okay I figured out roughly how to do it - ie a large enough value to show what N and P are approaching. I just had to restrict the domains futher than N>0 and P>0 (e.g. 0<N<25)... still not perfect (it won't let me sub in t=infinity or a very large number for t) but it'll do.