Displacement Time Graph

[dinosaur93]

Given only graphs

How do you convert a velocity time graph back to displacement time graph?

[b^3]

The displacement will be the area under the velocity time graph. So for example if you have a constant velocity of 5m/s. The displacement would be given by the area under this, so after 2 seconds, the displacement (i.e. area) would be 2*5=10m, after 10s displacement = 10*5=50m. Say after this 10 seconds the velocity decreases to 0 in 5s. Then the displacement will be the 50m plus the area under the triangle formed. So displacement = 50+(5*5)/2=62.5m. I hope that helps. So you can antidifferentiate it. Don't forget plus c.

EDIT: Sorry thought this was in the physics section, now realised it is methods.

[dinosaur93]

Can I draw the displacement time graph by basing it on the velocity GRAPHalone? (without equations)

Or should I first try and find the equation of the velocity graph and integrate it?

[b^3]

Can I draw the displacement time graph by basing it on the velocity GRAPHalone? (without equations)

Or should I first try and find the equation of the velocity graph and integrate it?

Depends on the situation, but it is probably better to find the equation, then draw it, that way mistakes are minismised.