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November 01, 2025, 08:05:33 pm
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Author Topic: QUESTION  (Read 628 times)  Share 

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david10d

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QUESTION
« on: October 07, 2011, 11:54:16 pm »
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just doing my first exam 2 to see where i'm at atm.


see VCAA 2006 exam 2

question 1e (find dA/dt). can someone explain this to me please? it seems so simple but i can't work it out =/ wtf


also what the fuck at these cunts not putting out solutions? lazy pricks



cheers
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2012: University of Melbourne - Bachelor of Commerce

vea

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Re: QUESTION
« Reply #1 on: October 07, 2011, 11:58:16 pm »
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A=piy^2
dA/dy=2pi y
use chain rule dA/dt=dA/dy x dy/dt
=24pix(6-3x^3)/91+x^3)^2
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david10d

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Re: QUESTION
« Reply #2 on: October 08, 2011, 12:03:35 am »
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Quote from: vea on October 07, 2011, 11:58:16 pm
A=piy^2
dA/dy=2pi y
use chain rule dA/dt=dA/dy x dy/dt
=24pix(6-3x^3)/91+x^3)^2


zzz

cheers dude
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2012: University of Melbourne - Bachelor of Commerce
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