The street pole transformer is the transformer right before the house.
The voltage in the secondary is 110 V RMS.
The voltage in the primary will be less than 9 kV RMS. The current in the primary will be less than 1.5 A.
It'll be less because there's probably a power loss in the lines. We are told that it's very close to 9 kV, so I'll just use that value.
The other possible trick is that the 1.5 A quoted may not be the RMS value. We know that the voltage's are RMS, as it is explicitly stated.
We are also told the transfomer is ideal, so the primary power will be the same as the secondary power (and the transformer equations will also apply).

We are trying to find current in the secondary (

)
We also know that it's a step down transformer. So a decrease in voltage will result in an increase in current, as power is constant (I=P/V). That can give us a clue if our answer is correct.


Does that answer make sense? I don't know.
I want to try another method:
We are given the primary current and voltage for the primary circuit.
We can figure out the power in the primary. This will be equal to the power in the secondary.
We know the voltage in the secondary (and now the power in the secondary). Therefore we can find out the current in the secondary.



Same answer, more intuitive reasoning. It makes sense the answer is the same, after all the transformer equations are derived from the power relationship.
Not entirely sure if the value for current is in RMS though, but I'm pretty sure it is.