Login

Search the forums now!

Welcome, Guest. Please login or register.

November 01, 2025, 12:36:20 pm
Pages: [1]   Go Down

Author Topic: electrochemistry  (Read 954 times)  Share 

0 Members and 1 Guest are viewing this topic.

peterb_7

  • Victorian
  • Fresh Poster
  • *
  • Posts: 1
  • Respect: 0
electrochemistry
« on: October 15, 2011, 05:53:23 pm »
0
Hey guys struggling with a question from Neap: diagnostic topic test - 2008 - test 8: electrochemistry

4d. Sulfuric acid is a strong oxidant with a standard reduction potential as shown below.

SO42-(aq) + 4H+ + 2e- ------> SO2(aq) + 2 H2O(l) E0 = 0.16 V

A 1.0 M solution of sulfuric acid is electrolysed using inert electrodes.
Explain why the product at the cathode is hydrogen and not sulfur dioxide

THANKS FOR THE HELP GUYS :D
Logged

BoredSatan

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1206
  • <3
  • Respect: +72
  • School: GWSC
  • School Grad Year: 2011
Re: electrochemistry
« Reply #1 on: October 15, 2011, 05:57:57 pm »
0
Sulfate is negatively charged, therefore it will not be attracted to the negatively charged cathods during electrolysis

the hydrogen ion will therefore by reduced to hydrogen gas
Logged
Master of Dentistry, Latrobe University 2011 ATAR: 99.75
ATARnotes Accounting Unit 3&4 Study Guide Author
Pages: [1]   Go Up