Advice for using a CAS in Extended Response Questions (Most applies to all CAS)
How to use a CAS to evaluate areas, showing full working
- Write down the integral statement for the area, for example, the integral of x^2 with respect to x from 0 to 5
- Type the function into the CAS, without the bounds, and get the antiderivative
- Now write the antiderivative and put in the correct bounds, using the square brackets
- Now, by hand, substitute the numbers into the anti-dervative, so F(a) - F(b), but don't evaluate it
- Go back to the CAS, and enter in the integral, this time with bounds, then copy the answer across to your paper
- So you've just worked out an area, supposedly showing "full working" and "using calculus" but you're assured of a right answer
How to use a CAS to find derivatives, showing full working
- Say we want to find the derivative of a complicated function, but it's worth 3 marks, this is what I'd do
- Determine the rule to be used. Say it's a quotient
- First, let u=... and v=...
- Now write down the rule dy/dx = (v.du/dx - u.dv/dx)/v^2
- Go to your CAS, and find du/dx and dv/dx
- Substitute all into the rule, but leave unsimplified - dy/dx = ( (......) x (........) - (.........) x (........))/(.......)
- Now use the CAS to find the derivative, dy/dx
- Copy it down, and voila, 100% correct derivative
Finding f(x) given f'(x) - a shortcut
- If we know a derivative and a point on the curve f(x), there is a shortcut to solving it
- It's using a command on the CAS called dSolve - for the ClassPad
- Go interactive, advanced, dSolve
- In the first column, type y'=...(derivative)...
- Independent Variable - x
- Dependent Variable - y
- Initial condition, type, for example if we had the point (1, 5) - "x=1,y=5"
Finding f(x) given f'(x) - a shortcut using definite integrals
- Similar to above but for people on TI Calcs - may be a fast way
- Type the integral sign with bounds, but instead of using x, use another letter, for example t
- So type in the integral sign, and then the derivative using t instead of x
- Now look at your initial conditions, say you have the point (0,5)
- Put the lower bound as your x-co-ordinate "0"
- Put the upper bound as the variable "x"
- Now after the integral (i.e. after the dt) put + the y-co-ordinate so here you would put +5
- Remember it's "dt" not "dx"
- Hit enter, and you should get your function of x
Finding a,b,c...etc in equations knowing the points
- You can use the regression function to check that your values are correct
- More to come, break time!