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November 01, 2025, 10:47:51 am

Author Topic: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8  (Read 732 times)  Share 

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onur369

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NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
« on: November 03, 2011, 10:37:04 pm »
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WHY IS THE ANSWER A ? ???? PLEASE NEED HELP
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Keo

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Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
« Reply #1 on: November 03, 2011, 10:42:17 pm »
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Flip the graph around its an increasing trend, this also shows that r > 1, it can't be c because it curves again. It increases negatively instead of positively. Good luck tomorrow! :)
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FromBaghdadWithLove

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Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
« Reply #2 on: November 03, 2011, 10:44:52 pm »
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hey onur bro just do trial and error stuff on ur calculator, dont panic most questions are straight forward...
Haven't decided...

DannyN

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Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
« Reply #3 on: November 03, 2011, 10:47:12 pm »
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remember the question doesnt state whether your initial value is postive or negatiuve, hopefully im explaining the right question doing this from memory, i remember every question in 08 onwards >.>
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geoff_821

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Re: NUMBER PATTERNS 2010 EXAM 1 QUESTION 8
« Reply #4 on: November 03, 2011, 10:51:34 pm »
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r>1 however "a" may be negative

Let's suppose a = -2 and r =2

t1 = ar^(n-1)
t1 = -2
t2 = -4
t3 = -8

Hope this helps