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November 01, 2025, 10:09:13 am

Author Topic: My proposed solutions for exam 2  (Read 6796 times)  Share 

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woolworth

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Re: My proposed solutions for exam 2
« Reply #15 on: November 07, 2011, 06:19:23 pm »
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i think the solns are right, except for that maximum almond one where i got 120 >.> in graphs & relns

Namit

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Re: My proposed solutions for exam 2
« Reply #16 on: November 07, 2011, 06:24:38 pm »
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Got a copy of the actual exam? Seems like you got some errors...


Nope, but do tell which things you think are errors.
These are confirmed by 2 people including my teacher.

Wasn't the last question in number patterns asking for what value gives 200000 in march?  I think you gave 3781,  i thought it may be 2000?

davidle_10

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Re: My proposed solutions for exam 2
« Reply #17 on: November 07, 2011, 06:26:34 pm »
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i think the solns are right, except for that maximum almond one where i got 120 >.> in graphs & relns
I got 125g..
You had to find inequation x+y >(greater or equal) 500
then rearrange to find y so y=500-x
Sub this into the equation 0.2x+0.04y=40
0.2x+0.04(500-x)=40
x=125g
2010: Methods
2011:English, Chemistry,Physics, Specialist, Further.

thatisanote

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Re: My proposed solutions for exam 2
« Reply #18 on: November 07, 2011, 09:09:41 pm »
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Got a copy of the actual exam? Seems like you got some errors...


Nope, but do tell which things you think are errors.
These are confirmed by 2 people including my teacher.

Wasn't the last question in number patterns asking for what value gives 200000 in march?  I think you gave 3781,  i thought it may be 2000?

Sorry this one was confirmed by my teacher, I watched him do it.
Work out the value for t3 (march), then go 200000-t3.
2010: Eco 46
2011: Eng 45 MMM 47 MFM 50 Phy 44 MUEP Comp Systems 5.5
2012: Stanford University :)

(selling SAT/american college books, pm me)

Namit

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Re: My proposed solutions for exam 2
« Reply #19 on: November 07, 2011, 09:27:59 pm »
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Okayyy, damn

some dude

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Re: My proposed solutions for exam 2
« Reply #20 on: November 07, 2011, 11:13:40 pm »
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for the geo answer of 1.4m^2 , didnt it ask for the area of the octagon. so
.5*2*2*sin(45)=1.4 *8 gives you 11.something. did u forget to times the 8, or am i missing something here?

woolworth

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Re: My proposed solutions for exam 2
« Reply #21 on: November 07, 2011, 11:34:51 pm »
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i think the solns are right, except for that maximum almond one where i got 120 >.> in graphs & relns
I got 125g..
You had to find inequation x+y >(greater or equal) 500
then rearrange to find y so y=500-x
Sub this into the equation 0.2x+0.04y=40
0.2x+0.04(500-x)=40
x=125g

yeh i know i got it wrong, i did the same thing, but somehow got 120g

thatisanote

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Re: My proposed solutions for exam 2
« Reply #22 on: November 08, 2011, 11:11:49 am »
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for the geo answer of 1.4m^2 , didnt it ask for the area of the octagon. so
.5*2*2*sin(45)=1.4 *8 gives you 11.something. did u forget to times the 8, or am i missing something here?

Nah just the triangle (OAB or something)
THen the next question you have to use PIr^2-area of octagon (which is 1.4*8)
2010: Eco 46
2011: Eng 45 MMM 47 MFM 50 Phy 44 MUEP Comp Systems 5.5
2012: Stanford University :)

(selling SAT/american college books, pm me)

some dude

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Re: My proposed solutions for exam 2
« Reply #23 on: November 08, 2011, 11:54:45 am »
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for the geo answer of 1.4m^2 , didnt it ask for the area of the octagon. so
.5*2*2*sin(45)=1.4 *8 gives you 11.something. did u forget to times the 8, or am i missing something here?

Nah just the triangle (OAB or something)
THen the next question you have to use PIr^2-area of octagon (which is 1.4*8)

ahh so thats 2 silly mistakes already...:/