Chem NEAP 2011

[geoff_821]

So after a long week of further, methods and english exams, I picked up a chem exam for the first time in about 2 weeks.
I am literally clueless on the questions they ask, I've forgotten everything.
So I need some help, I looked at the solutions and I'm just like 

Question 1
In a bomb calorimeter, the reaction vessel is surrounded by water. Since the amount of water may vary from
one experiment to the next, the mass of water used is measured in each experiment. The calibration factor of
the calorimeter is therefore broken into two parts: the water and the calorimeter components.
a. The calibration factor for one calorimeter containing 1.00 kg of water is 9.56 kJ°C–1.
Calculate the calibration factor for the calorimeter components, in kJ°C–1.

b. In a separate experiment, the bomb calorimeter used in part a is filled with 1058 g of water. The
initial temperature of the calorimeter contents is 22.8°C. A 3.05 g sample of 2-propanol undergoes
complete combustion in the calorimeter.
i. Calculate the energy released during the combustion reaction.

ii. Calculate the final temperature reached by the calorimeter contents.


Can someone tell me how to work these out?

[Panicmode]

See attached scan = D

[geoff_821]

wow thankyou! that's very kind of you!

Just a question, where did '1058' come from in part ii?

[Panicmode]

wow thankyou! that's very kind of you!

Just a question, where did '1058' come from in part ii?

The question stated that there was 1058 grams of water. To figure out the calibration factor of water I multiplied it's SHC by it's mass (which is essentially, mass x energy released x degrees)