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October 21, 2025, 06:48:00 pm

Author Topic: Chemistry Insight 2011 MC Q12  (Read 2401 times)  Share 

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dimmy18

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Chemistry Insight 2011 MC Q12
« on: November 13, 2011, 01:10:49 am »
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The question is:
Magnesium reacts with oxygen according to the thermochemical equation
2Mg + O2 -->  2MgO     H=-1200 kJ mol

The mass , in g, of magnesium that would need to be burned to release 4000kJ of energy is
A. 7.29
B. 14.6
C. 81.0
D. 162

The answer said D
However I think this is wrong. I think it should be C.

Energy required is simply 4000/1200, but what they've done is doubled it since there is a 2 in front of Mg.
However it is 2 mol for every 1200, so doubling would be finding 4 mol, hence the answer should be C.

Am I right?

(This is a pretty bad paper)

Edit: I posted this at 1 am so ignore everything I said above.
« Last Edit: November 13, 2011, 01:44:03 am by dimmy18 »

kenny_

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Re: Chemistry Insight 2011 MC Q12
« Reply #1 on: November 13, 2011, 01:23:15 am »
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You have to put the 2 there cause the delta H is per mol
« Last Edit: November 13, 2011, 01:40:31 am by kenny_ »

dimmy18

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Re: Chemistry Insight 2011 MC Q12
« Reply #2 on: November 13, 2011, 01:24:26 am »
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But it's technically per reaction...

If it were per mol of Mg it would be -600

kenny_

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Re: Chemistry Insight 2011 MC Q12
« Reply #3 on: November 13, 2011, 01:26:37 am »
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Look at page 11 of your data book and write out balanced equations for each of the combustion reactions. The delta H is per mol regardless of the number in front of the fuels
« Last Edit: November 13, 2011, 01:44:45 am by kenny_ »

Zebra

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Re: Chemistry Insight 2011 MC Q12
« Reply #4 on: November 13, 2011, 01:30:35 am »
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Look at page 11 of your data book and write out balanced equations for each of the combustion reactions. The delta H is per mol regardless of the number in front of the fuels

wtf? energy given in data book can be taken as per mole.... no?
2010:
Mathematical Methods CAS 3/4 [41->45.8]

2011:
English Second Language 3/4 [46->47.1], Chemistry 3/4 [42->45.6], Specialist Maths 3/4 [38->49.2], LOTE [33->40.9], Biology 3/4 [41->42]

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dimmy18

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Re: Chemistry Insight 2011 MC Q12
« Reply #5 on: November 13, 2011, 01:31:30 am »
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The data booklet give delta H for one mol but when you write out the equation you need to adjust the delta H to match the number before the substance...

kenny_

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Re: Chemistry Insight 2011 MC Q12
« Reply #6 on: November 13, 2011, 01:32:00 am »
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Look at page 11 of your data book and write out balanced equations for each of the combustion reactions. The delta H is per mol regardless of the number in front of the fuels

wtf? energy given in data book can be taken as per mole.... no?

yes...?

Zebra

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Re: Chemistry Insight 2011 MC Q12
« Reply #7 on: November 13, 2011, 01:32:41 am »
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sorry its late any my brains cookin'
2010:
Mathematical Methods CAS 3/4 [41->45.8]

2011:
English Second Language 3/4 [46->47.1], Chemistry 3/4 [42->45.6], Specialist Maths 3/4 [38->49.2], LOTE [33->40.9], Biology 3/4 [41->42]

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dimmy18

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Re: Chemistry Insight 2011 MC Q12
« Reply #8 on: November 13, 2011, 01:37:07 am »
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This is a quote from wikipedia (reliable)

The enthalpy of combustion for hydrogen is −286 kJ/mol:[12]
2 H2(g) + O2(g) → 2 H2O(l) + 572 kJ (286 kJ/mol)[

check yourself if you want http://en.wikipedia.org/wiki/Hydrogen

kenny_

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Re: Chemistry Insight 2011 MC Q12
« Reply #9 on: November 13, 2011, 01:39:28 am »
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The question is:
Magnesium reacts with oxygen according to the thermochemical equation
2Mg + O2 -->  2MgO     H=-1200 kJ mol

The mass , in g, of magnesium that would need to be burned to release 4000kJ of energy is
A. 7.29
B. 14.6
C. 81.0
D. 162

The answer said D
However I think this is wrong. I think it should be C.

Energy required is simply 4000/1200, but what they've done is doubled it since there is a 2 in front of Mg.
However it is 2 mol for every 1200, so doubling would be finding 4 mol, hence the answer should be C.

Am I right?

(This is a pretty bad paper)

Wait a second, to find the energy released you do a ratio.

x/2 = 4000/1200
x = 2 x 4000/1200 mol

dimmy18

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Re: Chemistry Insight 2011 MC Q12
« Reply #10 on: November 13, 2011, 01:43:09 am »
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The question is:
Magnesium reacts with oxygen according to the thermochemical equation
2Mg + O2 -->  2MgO     H=-1200 kJ mol

The mass , in g, of magnesium that would need to be burned to release 4000kJ of energy is
A. 7.29
B. 14.6
C. 81.0
D. 162

The answer said D
However I think this is wrong. I think it should be C.

Energy required is simply 4000/1200, but what they've done is doubled it since there is a 2 in front of Mg.
However it is 2 mol for every 1200, so doubling would be finding 4 mol, hence the answer should be C.

Am I right?

(This is a pretty bad paper)

Wait a second, to find the energy released you do a ratio.

x/2 = 4000/1200
x = 2 x 4000/1200 mol

Ok.. let me explain it.

2 mol of Mg will give me 1200 KJ
then x mol will give me 4000KJ

Therefore I need...

Oh wait... I see now! (my bad)

kenny_

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Re: Chemistry Insight 2011 MC Q12
« Reply #11 on: November 13, 2011, 01:44:17 am »
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The question is:
Magnesium reacts with oxygen according to the thermochemical equation
2Mg + O2 -->  2MgO     H=-1200 kJ mol

The mass , in g, of magnesium that would need to be burned to release 4000kJ of energy is
A. 7.29
B. 14.6
C. 81.0
D. 162

The answer said D
However I think this is wrong. I think it should be C.

Energy required is simply 4000/1200, but what they've done is doubled it since there is a 2 in front of Mg.
However it is 2 mol for every 1200, so doubling would be finding 4 mol, hence the answer should be C.

Am I right?

(This is a pretty bad paper)

Wait a second, to find the energy released you do a ratio.

x/2 = 4000/1200
x = 2 x 4000/1200 mol

Ok.. let me explain it.

2 mol of Mg will give me 1200 KJ
then x mol will give me 4000KJ

Therefore I need...

Oh wait... I see now! (my bad)

Yeah, the way you did it first, you took it as per mol, then it confused me

Panicmode

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Re: Chemistry Insight 2011 MC Q12
« Reply #12 on: November 13, 2011, 01:46:03 am »
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2   gives 1200

x   gives  4000

Cross multiply

2 x 4000 = 1200x

x = 8000/1200


Figure out mass from there...


Ah crap. Beaten to the punch.
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